зеркало из https://github.com/microsoft/git.git
Revert "unpack_trees(): skip trees that are the same in all input"
This reverts commit 83c90314aa
, which
seems to have broken merge to report conflicts when there should be
none.
This commit is contained in:
Родитель
3952710bfa
Коммит
4e363b11bd
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@ -427,10 +427,6 @@ static int switch_cache_bottom(struct traverse_info *info)
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return ret;
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return ret;
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}
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}
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static int fast_forward_merge(int n, unsigned long dirmask,
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struct name_entry *names,
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struct traverse_info *info);
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static int traverse_trees_recursive(int n, unsigned long dirmask,
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static int traverse_trees_recursive(int n, unsigned long dirmask,
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unsigned long df_conflicts,
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unsigned long df_conflicts,
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struct name_entry *names,
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struct name_entry *names,
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@ -442,11 +438,6 @@ static int traverse_trees_recursive(int n, unsigned long dirmask,
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struct traverse_info newinfo;
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struct traverse_info newinfo;
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struct name_entry *p;
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struct name_entry *p;
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if (!df_conflicts) {
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int status = fast_forward_merge(n, dirmask, names, info);
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if (status)
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return status;
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}
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p = names;
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p = names;
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while (!p->mode)
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while (!p->mode)
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p++;
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p++;
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@ -694,53 +685,6 @@ static struct cache_entry *find_cache_entry(struct traverse_info *info,
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return NULL;
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return NULL;
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}
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}
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static int fast_forward_merge(int n, unsigned long dirmask,
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struct name_entry *names,
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struct traverse_info *info)
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{
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int i;
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struct cache_entry *src[MAX_UNPACK_TREES + 1] = { NULL, };
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struct unpack_trees_options *o = info->data;
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/* merging two or more trees with an identical subdirectory? */
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if ((n < 2) || ((1UL << n) - 1) != dirmask ||
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!o->merge || o->reset || o->initial_checkout)
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return 0;
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for (i = 1; i < n; i++)
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if (hashcmp(names[i-1].sha1, names[i].sha1))
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return 0;
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/*
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* Instead of descending into the directory, keep the contents
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* of the current index.
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*/
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while (1) {
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struct cache_entry *ce;
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ce = next_cache_entry(o);
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if (!ce)
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break;
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/* Is the entry still in that directory? */
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if (do_compare_entry(ce, info, names))
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break;
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/*
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* Note: we do not just run unpack_index_entry() here,
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* as the callback may want to compare what is in the
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* index with what are from the HEAD and the other tree
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* and reject the merge. We pretend that ancestors, the
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* HEAD and the other tree all have the same contents as
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* the current index, which is a lie, but it works.
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*/
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for (i = 0; i < n + 1; i++)
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src[i] = ce;
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mark_ce_used(ce, o);
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if (call_unpack_fn(src, o) < 0)
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return unpack_failed(o, NULL);
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if (ce_stage(ce))
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mark_ce_used_same_name(ce, o);
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}
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return dirmask;
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}
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static void debug_path(struct traverse_info *info)
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static void debug_path(struct traverse_info *info)
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{
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{
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if (info->prev) {
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if (info->prev) {
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