refactor find_ref_by_name() to accept const list

Since it doesn't actually touch its argument, this makes
sense.

However, we still want to return a non-const version (which
requires a cast) so that this:

  struct ref *a, *b;
  a = find_ref_by_name(b);

works. Unfortunately, you can also silently strip the const
from a variable:

  struct ref *a;
  const struct ref *b;
  a = find_ref_by_name(b);

This is a classic C const problem because there is no way to
say "return the type with the same constness that was passed
to us"; we provide the same semantics as standard library
functions like strchr.

Signed-off-by: Jeff King <peff@peff.net>
Signed-off-by: Jay Soffian <jaysoffian@gmail.com>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
Jeff King 2009-02-25 03:32:10 -05:00 коммит произвёл Junio C Hamano
Родитель 119c8eeede
Коммит 5483f79998
2 изменённых файлов: 3 добавлений и 3 удалений

Просмотреть файл

@ -801,7 +801,7 @@ struct ref {
#define REF_HEADS (1u << 1)
#define REF_TAGS (1u << 2)
extern struct ref *find_ref_by_name(struct ref *list, const char *name);
extern struct ref *find_ref_by_name(const struct ref *list, const char *name);
#define CONNECT_VERBOSE (1u << 0)
extern struct child_process *git_connect(int fd[2], const char *url, const char *prog, int flags);

4
refs.c
Просмотреть файл

@ -1628,10 +1628,10 @@ int update_ref(const char *action, const char *refname,
return 0;
}
struct ref *find_ref_by_name(struct ref *list, const char *name)
struct ref *find_ref_by_name(const struct ref *list, const char *name)
{
for ( ; list; list = list->next)
if (!strcmp(list->name, name))
return list;
return (struct ref *)list;
return NULL;
}