diff-tree: do not default to -c

Marco says it breaks qgit.  This makes the flags a bit more
orthogonal.

  $ git-diff-tree -r --abbrev ca18

    No output from this command because you asked to skip merge by
    not having -m there.

  $ git-diff-tree -r -m --abbrev ca18
  ca182053c7
  :100644 100644 538d21d... 59042d1... M	Makefile
  :100644 100644 410b758... 6c47c3a... M	entry.c
  ca182053c7
  :100644 100644 30479b4... 59042d1... M	Makefile

    The same "independent sets of diff" as before without -c.

  $ git-diff-tree -r -m -c --abbrev ca18
  ca182053c7
  ::100644 100644 100644 538d21d... 30479b4... 59042d1... MM	Makefile

    Combined.

  $ git-diff-tree -r -c --abbrev ca18
  ca182053c7
  ::100644 100644 100644 538d21d... 30479b4... 59042d1... MM	Makefile

    Asking for combined without -m does not make sense, so -c
    implies -m.

We need to supply -c as default to whatchanged, which is a
one-liner.

Signed-off-by: Junio C Hamano <junkio@cox.net>
This commit is contained in:
Junio C Hamano 2006-02-11 16:43:30 -08:00
Родитель 16139f9035
Коммит 6932c78cb4
2 изменённых файлов: 3 добавлений и 3 удалений

Просмотреть файл

@ -6,7 +6,7 @@ static int show_root_diff = 0;
static int no_commit_id = 0;
static int verbose_header = 0;
static int ignore_merges = 1;
static int combine_merges = 1;
static int combine_merges = 0;
static int dense_combined_merges = 0;
static int read_stdin = 0;
static int always_show_header = 0;
@ -248,7 +248,7 @@ int main(int argc, const char **argv)
continue;
}
if (!strcmp(arg, "-m")) {
combine_merges = ignore_merges = 0;
ignore_merges = 0;
continue;
}
if (!strcmp(arg, "-c")) {

Просмотреть файл

@ -10,7 +10,7 @@ case "$0" in
count=
test -z "$diff_tree_flags" &&
diff_tree_flags=$(git-repo-config --get whatchanged.difftree)
diff_tree_default_flags='-M --abbrev' ;;
diff_tree_default_flags='-c -M --abbrev' ;;
*show)
count=-n1
test -z "$diff_tree_flags" &&