fetch-pack: refactor parsing in get_ack

There are several uses of the magic number "line+45" when
parsing ACK lines from the server, and it's rather unclear
why 45 is the correct number. We can make this more clear by
keeping a running pointer as we parse, using skip_prefix to
jump past the first "ACK ", then adding 40 to jump past
get_sha1_hex (which is still magical, but hopefully 40 is
less magical to readers of git code).

Note that this actually puts us at line+44. The original
required some character between the sha1 and further ACK
flags (it is supposed to be a space, but we never enforced
that). We start our search for flags at line+44, which
meanas we are slightly more liberal than the old code.

Signed-off-by: Jeff King <peff@peff.net>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
Jeff King 2014-06-18 15:56:03 -04:00 коммит произвёл Junio C Hamano
Родитель e814c39c2f
Коммит 82e56767aa
1 изменённых файлов: 9 добавлений и 6 удалений

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@ -189,20 +189,23 @@ static enum ack_type get_ack(int fd, unsigned char *result_sha1)
{
int len;
char *line = packet_read_line(fd, &len);
const char *arg;
if (!len)
die("git fetch-pack: expected ACK/NAK, got EOF");
if (!strcmp(line, "NAK"))
return NAK;
if (starts_with(line, "ACK ")) {
if (!get_sha1_hex(line+4, result_sha1)) {
if (len < 45)
if (skip_prefix(line, "ACK ", &arg)) {
if (!get_sha1_hex(arg, result_sha1)) {
arg += 40;
len -= arg - line;
if (len < 1)
return ACK;
if (strstr(line+45, "continue"))
if (strstr(arg, "continue"))
return ACK_continue;
if (strstr(line+45, "common"))
if (strstr(arg, "common"))
return ACK_common;
if (strstr(line+45, "ready"))
if (strstr(arg, "ready"))
return ACK_ready;
return ACK;
}