From 915e44c6357f3bd9d5fa498a201872c4367302d3 Mon Sep 17 00:00:00 2001 From: Stefan Beller Date: Mon, 23 Mar 2015 10:57:11 -0700 Subject: [PATCH] read-cache: fix memleak `ce` is allocated in make_cache_entry and should be freed if it is not used any more. refresh_cache_entry as a wrapper around refresh_cache_ent will either return - the `ce` given as the parameter, when it was up-to-date; - a new updated cache entry which is allocated to new memory; or - a NULL when refreshing failed. In the latter two cases, the original cache-entry `ce` is not used and needs to be freed. The rule can be expressed as "if the return value from refresh is different from the original ce, ce is no longer used." Helped-by: Junio C Hamano Signed-off-by: Stefan Beller Signed-off-by: Junio C Hamano --- read-cache.c | 7 ++----- 1 file changed, 2 insertions(+), 5 deletions(-) diff --git a/read-cache.c b/read-cache.c index 5b922fd583..0052b72d9c 100644 --- a/read-cache.c +++ b/read-cache.c @@ -748,12 +748,9 @@ struct cache_entry *make_cache_entry(unsigned int mode, ce->ce_mode = create_ce_mode(mode); ret = refresh_cache_entry(ce, refresh_options); - if (!ret) { + if (ret != ce) free(ce); - return NULL; - } else { - return ret; - } + return ret; } int ce_same_name(const struct cache_entry *a, const struct cache_entry *b)