revision traversal: SHOWN means shown

This moves the code to set SHOWN on the commit from get_revision_1()
back to get_revision(), so that the bit means what it originally
meant: this commit has been given back to the caller.

Also it fixes the --reverse breakage Dscho pointed out.

Signed-off-by: Junio C Hamano <junkio@cox.net>
This commit is contained in:
Junio C Hamano 2007-03-05 18:23:57 -08:00
Родитель c2dea5a11c
Коммит c33d859385
1 изменённых файлов: 18 добавлений и 8 удалений

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@ -1227,7 +1227,6 @@ static struct commit *get_revision_1(struct rev_info *revs)
if (revs->parents)
rewrite_parents(revs, commit);
}
commit->object.flags |= SHOWN;
return commit;
} while (revs->commits);
return NULL;
@ -1280,11 +1279,22 @@ struct commit *get_revision(struct rev_info *revs)
}
if (revs->reverse) {
int limit = -1;
if (0 <= revs->max_count) {
limit = revs->max_count;
if (0 < revs->skip_count)
limit += revs->skip_count;
}
l = NULL;
while ((c = get_revision_1(revs)))
while ((c = get_revision_1(revs))) {
commit_list_insert(c, &l);
if ((0 < limit) && !--limit)
break;
}
revs->commits = l;
revs->reverse = 0;
revs->max_count = -1;
c = NULL;
}
@ -1298,8 +1308,6 @@ struct commit *get_revision(struct rev_info *revs)
c = get_revision_1(revs);
if (!c)
break;
/* Although we grabbed it, it is not shown. */
c->object.flags &= ~SHOWN;
}
/*
@ -1310,16 +1318,18 @@ struct commit *get_revision(struct rev_info *revs)
break;
case 0:
/* Although we grabbed it, it is not shown. */
if (c)
c->object.flags &= ~SHOWN;
c = NULL;
break;
default:
revs->max_count--;
}
if (!revs->boundary)
if (c)
c->object.flags |= SHOWN;
if (!revs->boundary) {
return c;
}
if (!c) {
/*
@ -1341,7 +1351,7 @@ struct commit *get_revision(struct rev_info *revs)
for (l = c->parents; l; l = l->next) {
struct object *p;
p = &(l->item->object);
if (p->flags & CHILD_SHOWN)
if (p->flags & (CHILD_SHOWN | SHOWN))
continue;
p->flags |= CHILD_SHOWN;
gc_boundary(&revs->boundary_commits);