git-remote: show all remotes with "git remote show"

Many other commands use the "no arguments" form to show a
list (e.g., git-branch, git-tag). While we did show all
remotes for just "git remote", we displayed a usage error
for "git remote show" with no arguments. This is
counterintuitive, since by giving it _more_ information, we
get _less_ result.

The usage model can now be thought of as:

  - "git remote show <remote>": show a remote
  - "git remote show": show all remotes
  - "git remote": assume "show"; i.e., shorthand for "git remote show"

Signed-off-by: Jeff King <peff@peff.net>
Acked-by: Johannes Schindelin <Johannes.Schindelin@gmx.de>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
Jeff King 2008-04-09 11:15:51 -04:00 коммит произвёл Junio C Hamano
Родитель 71349732c5
Коммит c4112bb6bb
1 изменённых файлов: 6 добавлений и 1 удалений

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@ -19,6 +19,8 @@ static const char * const builtin_remote_usage[] = {
static int verbose;
static int show_all(void);
static inline int postfixcmp(const char *string, const char *postfix)
{
int len1 = strlen(string), len2 = strlen(postfix);
@ -380,8 +382,11 @@ static int show_or_prune(int argc, const char **argv, int prune)
argc = parse_options(argc, argv, options, builtin_remote_usage, 0);
if (argc < 1)
if (argc < 1) {
if (!prune)
return show_all();
usage_with_options(builtin_remote_usage, options);
}
memset(&states, 0, sizeof(states));
for (; argc; argc--, argv++) {