Documentation: unbreak regex in show-ref manual

I am not sure why, but the regular expression "(?:\^\{\})" gets
rendered by asciidoc as "(?:\{})".  The intent seems to be a regex
matching the literal string "^{}", so this rewrites the markup to
produce "(?:\^{})" as output.

Cc: Julian Phillips <julian@quantumfyre.co.uk>
Signed-off-by: Jonathan Nieder <jrnieder@gmail.com>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
Jonathan Nieder 2010-08-20 05:23:54 -05:00 коммит произвёл Junio C Hamano
Родитель 438ded457b
Коммит f1005987e2
2 изменённых файлов: 3 добавлений и 2 удалений

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@ -16,6 +16,7 @@ plus=&#43;
caret=&#94;
startsb=&#91;
endsb=&#93;
backslash=&#92;
tilde=&#126;
apostrophe=&#39;
backtick=&#96;

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@ -73,8 +73,8 @@ OPTIONS
--exclude-existing[=<pattern>]::
Make 'git show-ref' act as a filter that reads refs from stdin of the
form "^(?:<anything>\s)?<refname>(?:\^\{\})?$" and performs the
following actions on each:
form "^(?:<anything>\s)?<refname>(?:{backslash}{caret}\{\})?$"
and performs the following actions on each:
(1) strip "^{}" at the end of line if any;
(2) ignore if pattern is provided and does not head-match refname;
(3) warn if refname is not a well-formed refname and skip;