argv-array: refactor empty_argv initialization

An empty argv-array is initialized to point to a static
empty NULL-terminated array.  The original implementation
separates the actual storage of the NULL-terminator from the
pointer to the list.  This makes the exposed type a "const
char **", which nicely matches the type stored by the
argv-array.

However, this indirection means that one cannot use
empty_argv to initialize a static variable, since it is
not a constant.

Instead, we can expose empty_argv directly, as an array of
pointers. The only place we use it is in the ARGV_ARRAY_INIT
initializer, and it decays to a pointer appropriately there.

Signed-off-by: Jeff King <peff@peff.net>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
Jeff King 2012-04-18 14:08:49 -07:00 коммит произвёл Junio C Hamano
Родитель 7e52f5660e
Коммит fd93d2e60e
2 изменённых файлов: 2 добавлений и 3 удалений

Просмотреть файл

@ -2,8 +2,7 @@
#include "argv-array.h"
#include "strbuf.h"
static const char *empty_argv_storage = NULL;
const char **empty_argv = &empty_argv_storage;
const char *empty_argv[] = { NULL };
void argv_array_init(struct argv_array *array)
{

Просмотреть файл

@ -1,7 +1,7 @@
#ifndef ARGV_ARRAY_H
#define ARGV_ARRAY_H
extern const char **empty_argv;
extern const char *empty_argv[];
struct argv_array {
const char **argv;