15 строки
466 B
Python
15 строки
466 B
Python
# Copyright (c) Microsoft Corporation. All rights reserved.
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# Licensed under the MIT License.
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import os
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# Unless manually modified, python3 should be the name of the current jupyter kernel
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# that runs on the activated conda environment
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KERNEL_NAME = "python3"
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OUTPUT_NOTEBOOK = "output.ipynb"
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def path_notebooks():
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"""Returns the path of the notebooks folder"""
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return os.path.abspath(os.path.join(os.path.dirname(__file__), os.path.pardir, "examples"))
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