Fix a bug in inverse halfright 32x32 transform

Fix a bug in the C implementation of the ihalfright32
transform, in the case that its input and output buffers are the same.
This occurs when it is called by av1_iht32x16_512_add_c.

Change-Id: I61c652e2662178520c0639a2879ae128a9c7ec3f
This commit is contained in:
Debargha Mukherjee 2016-10-12 10:49:29 -07:00
Родитель 933bf08cfb
Коммит e52816bf8f
1 изменённых файлов: 10 добавлений и 7 удалений

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@ -33,6 +33,9 @@ int get_tx_scale(const MACROBLOCKD *const xd, const TX_TYPE tx_type,
return txsize_sqr_up_map[tx_size] == TX_32X32;
}
// NOTE: The implementation of all inverses need to be aware of the fact
// that input and output could be the same buffer.
#if CONFIG_EXT_TX
static void iidtx4_c(const tran_low_t *input, tran_low_t *output) {
int i;
@ -56,17 +59,17 @@ static void iidtx32_c(const tran_low_t *input, tran_low_t *output) {
for (i = 0; i < 32; ++i) output[i] = input[i] * 4;
}
// For use in lieu of DST
// For use in lieu of ADST
static void ihalfright32_c(const tran_low_t *input, tran_low_t *output) {
int i;
tran_low_t inputhalf[16];
for (i = 0; i < 16; ++i) {
output[i] = input[16 + i] * 4;
}
// Multiply input by sqrt(2)
for (i = 0; i < 16; ++i) {
inputhalf[i] = (tran_low_t)dct_const_round_shift(input[i] * Sqrt2);
}
for (i = 0; i < 16; ++i) {
output[i] = input[16 + i] * 4;
}
idct16_c(inputhalf, output + 16);
// Note overall scaling factor is 4 times orthogonal
}
@ -106,14 +109,14 @@ static void highbd_ihalfright32_c(const tran_low_t *input, tran_low_t *output,
int bd) {
int i;
tran_low_t inputhalf[16];
for (i = 0; i < 16; ++i) {
output[i] = input[16 + i] * 4;
}
// Multiply input by sqrt(2)
for (i = 0; i < 16; ++i) {
inputhalf[i] =
HIGHBD_WRAPLOW(highbd_dct_const_round_shift(input[i] * Sqrt2), bd);
}
for (i = 0; i < 16; ++i) {
output[i] = input[16 + i] * 4;
}
aom_highbd_idct16_c(inputhalf, output + 16, bd);
// Note overall scaling factor is 4 times orthogonal
}