2013-07-24 11:41:39 +04:00
|
|
|
/* -*- Mode: C++; tab-width: 8; indent-tabs-mode: nil; c-basic-offset: 2 -*- */
|
|
|
|
/* vim: set ts=8 sts=2 et sw=2 tw=80: */
|
2013-07-03 04:25:13 +04:00
|
|
|
/* This Source Code Form is subject to the terms of the Mozilla Public
|
|
|
|
* License, v. 2.0. If a copy of the MPL was not distributed with this
|
|
|
|
* file, You can obtain one at http://mozilla.org/MPL/2.0/. */
|
|
|
|
|
|
|
|
/* C++11-style, but C++98-usable, "move references" implementation. */
|
|
|
|
|
2013-07-24 11:41:39 +04:00
|
|
|
#ifndef mozilla_Move_h
|
|
|
|
#define mozilla_Move_h
|
2013-07-03 04:25:13 +04:00
|
|
|
|
|
|
|
namespace mozilla {
|
|
|
|
|
|
|
|
/*
|
|
|
|
* "Move" References
|
|
|
|
*
|
|
|
|
* Some types can be copied much more efficiently if we know the original's
|
|
|
|
* value need not be preserved --- that is, if we are doing a "move", not a
|
|
|
|
* "copy". For example, if we have:
|
|
|
|
*
|
|
|
|
* Vector<T> u;
|
|
|
|
* Vector<T> v(u);
|
|
|
|
*
|
|
|
|
* the constructor for v must apply a copy constructor to each element of u ---
|
|
|
|
* taking time linear in the length of u. However, if we know we will not need u
|
|
|
|
* any more once v has been initialized, then we could initialize v very
|
|
|
|
* efficiently simply by stealing u's dynamically allocated buffer and giving it
|
|
|
|
* to v --- a constant-time operation, regardless of the size of u.
|
|
|
|
*
|
|
|
|
* Moves often appear in container implementations. For example, when we append
|
|
|
|
* to a vector, we may need to resize its buffer. This entails moving each of
|
|
|
|
* its extant elements from the old, smaller buffer to the new, larger buffer.
|
|
|
|
* But once the elements have been migrated, we're just going to throw away the
|
|
|
|
* old buffer; we don't care if they still have their values. So if the vector's
|
|
|
|
* element type can implement "move" more efficiently than "copy", the vector
|
|
|
|
* resizing should by all means use a "move" operation. Hash tables also need to
|
|
|
|
* be resized.
|
|
|
|
*
|
|
|
|
* The details of the optimization, and whether it's worth applying, vary from
|
|
|
|
* one type to the next. And while some constructor calls are moves, many really
|
|
|
|
* are copies, and can't be optimized this way. So we need:
|
|
|
|
*
|
|
|
|
* 1) a way for a particular invocation of a copy constructor to say that it's
|
|
|
|
* really a move, and that the value of the original isn't important
|
|
|
|
* afterwards (although it must still be safe to destroy); and
|
|
|
|
*
|
|
|
|
* 2) a way for a type (like Vector) to announce that it can be moved more
|
|
|
|
* efficiently than it can be copied, and provide an implementation of that
|
|
|
|
* move operation.
|
|
|
|
*
|
|
|
|
* The Move(T&) function takes a reference to a T, and returns a MoveRef<T>
|
|
|
|
* referring to the same value; that's 1). A MoveRef<T> is simply a reference
|
|
|
|
* to a T, annotated to say that a copy constructor applied to it may move that
|
|
|
|
* T, instead of copying it. Finally, a constructor that accepts an MoveRef<T>
|
|
|
|
* should perform a more efficient move, instead of a copy, providing 2).
|
|
|
|
*
|
|
|
|
* So, where we might define a copy constructor for a class C like this:
|
|
|
|
*
|
|
|
|
* C(const C& rhs) { ... copy rhs to this ... }
|
|
|
|
*
|
|
|
|
* we would declare a move constructor like this:
|
|
|
|
*
|
|
|
|
* C(MoveRef<C> rhs) { ... move rhs to this ... }
|
|
|
|
*
|
|
|
|
* And where we might perform a copy like this:
|
|
|
|
*
|
|
|
|
* C c2(c1);
|
|
|
|
*
|
|
|
|
* we would perform a move like this:
|
|
|
|
*
|
|
|
|
* C c2(Move(c1))
|
|
|
|
*
|
|
|
|
* Note that MoveRef<T> implicitly converts to T&, so you can pass a MoveRef<T>
|
|
|
|
* to an ordinary copy constructor for a type that doesn't support a special
|
|
|
|
* move constructor, and you'll just get a copy. This means that templates can
|
|
|
|
* use Move whenever they know they won't use the original value any more, even
|
|
|
|
* if they're not sure whether the type at hand has a specialized move
|
|
|
|
* constructor. If it doesn't, the MoveRef<T> will just convert to a T&, and
|
|
|
|
* the ordinary copy constructor will apply.
|
|
|
|
*
|
|
|
|
* A class with a move constructor can also provide a move assignment operator,
|
|
|
|
* which runs this's destructor, and then applies the move constructor to
|
|
|
|
* *this's memory. A typical definition:
|
|
|
|
*
|
|
|
|
* C& operator=(MoveRef<C> rhs) {
|
|
|
|
* this->~C();
|
|
|
|
* new(this) C(rhs);
|
|
|
|
* return *this;
|
|
|
|
* }
|
|
|
|
*
|
|
|
|
* With that in place, one can write move assignments like this:
|
|
|
|
*
|
|
|
|
* c2 = Move(c1);
|
|
|
|
*
|
|
|
|
* This destroys c1, moves c1's value to c2, and leaves c1 in an undefined but
|
|
|
|
* destructible state.
|
|
|
|
*
|
|
|
|
* This header file defines MoveRef and Move in the mozilla namespace. It's up
|
|
|
|
* to individual containers to annotate moves as such, by calling Move; and it's
|
|
|
|
* up to individual types to define move constructors.
|
|
|
|
*
|
|
|
|
* One hint: if you're writing a move constructor where the type has members
|
|
|
|
* that should be moved themselves, it's much nicer to write this:
|
|
|
|
*
|
2013-07-15 21:40:30 +04:00
|
|
|
* C(MoveRef<C> c) : x(Move(c->x)), y(Move(c->y)) { }
|
2013-07-03 04:25:13 +04:00
|
|
|
*
|
|
|
|
* than the equivalent:
|
|
|
|
*
|
2013-07-15 21:40:30 +04:00
|
|
|
* C(MoveRef<C> c) { new(&x) X(Move(c->x)); new(&y) Y(Move(c->y)); }
|
2013-07-03 04:25:13 +04:00
|
|
|
*
|
|
|
|
* especially since GNU C++ fails to notice that this does indeed initialize x
|
|
|
|
* and y, which may matter if they're const.
|
|
|
|
*/
|
|
|
|
template<typename T>
|
|
|
|
class MoveRef
|
|
|
|
{
|
|
|
|
T* pointer;
|
|
|
|
|
|
|
|
public:
|
|
|
|
explicit MoveRef(T& t) : pointer(&t) { }
|
|
|
|
T& operator*() const { return *pointer; }
|
|
|
|
T* operator->() const { return pointer; }
|
|
|
|
operator T& () const { return *pointer; }
|
|
|
|
};
|
|
|
|
|
|
|
|
template<typename T>
|
|
|
|
inline MoveRef<T>
|
|
|
|
Move(T& t)
|
|
|
|
{
|
|
|
|
return MoveRef<T>(t);
|
|
|
|
}
|
|
|
|
|
|
|
|
template<typename T>
|
|
|
|
inline MoveRef<T>
|
|
|
|
Move(const T& t)
|
|
|
|
{
|
2013-07-13 23:54:18 +04:00
|
|
|
// With some versions of gcc, for a class C, there's an (incorrect) ambiguity
|
|
|
|
// between the C(const C&) constructor and the default C(C&&) C++11 move
|
|
|
|
// constructor, when the constructor is called with a const C& argument.
|
|
|
|
//
|
|
|
|
// This ambiguity manifests with the Move implementation above when Move is
|
|
|
|
// passed const U& for some class U. Calling Move(const U&) returns a
|
|
|
|
// MoveRef<const U&>, which is then commonly passed to the U constructor,
|
|
|
|
// triggering an implicit conversion to const U&. gcc doesn't know whether to
|
|
|
|
// call U(const U&) or U(U&&), so it wrongly reports a compile error.
|
|
|
|
//
|
|
|
|
// http://gcc.gnu.org/bugzilla/show_bug.cgi?id=50442 has since been fixed, so
|
|
|
|
// this is no longer an issue for up-to-date compilers. But there's no harm
|
|
|
|
// in keeping it around for older compilers, so we might as well. See also
|
|
|
|
// bug 686280.
|
2013-07-03 04:25:13 +04:00
|
|
|
return MoveRef<T>(const_cast<T&>(t));
|
|
|
|
}
|
|
|
|
|
2013-07-04 02:57:33 +04:00
|
|
|
/** Swap |t| and |u| using move-construction if possible. */
|
|
|
|
template<typename T>
|
|
|
|
inline void
|
|
|
|
Swap(T& t, T& u)
|
|
|
|
{
|
|
|
|
T tmp(Move(t));
|
|
|
|
t = Move(u);
|
|
|
|
u = Move(tmp);
|
|
|
|
}
|
|
|
|
|
2013-07-03 04:25:13 +04:00
|
|
|
} // namespace mozilla
|
|
|
|
|
2013-07-24 11:41:39 +04:00
|
|
|
#endif /* mozilla_Move_h */
|