Bug 769504 - Atomize strings when using them as hash keys in a Map or Set. r=luke.

--HG--
extra : rebase_source : ba057a23415f4bca85d5c15c555db9fd10b5146e
This commit is contained in:
Jason Orendorff 2012-07-04 10:24:20 -05:00
Родитель 05300b47d1
Коммит 99924a9155
1 изменённых файлов: 7 добавлений и 18 удалений

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@ -644,9 +644,9 @@ class OrderedHashSet
bool
HashableValue::setValue(JSContext *cx, const Value &v)
{
if (v.isString() && v.toString()->isRope()) {
// Flatten this rope so that equals() is infallible.
JSString *str = v.toString()->ensureLinear(cx);
if (v.isString()) {
// Atomize so that hash() and equals() are fast and infallible.
JSString *str = js_AtomizeString(cx, v.toString(), DoNotInternAtom);
if (!str)
return false;
value = StringValue(str);
@ -676,26 +676,15 @@ HashableValue::hash() const
{
// HashableValue::setValue normalizes values so that the SameValue relation
// on HashableValues is the same as the == relationship on
// value.data.asBits, except for strings.
if (value.isString()) {
JSLinearString &s = value.toString()->asLinear();
return HashChars(s.chars(), s.length());
}
// Having dispensed with strings, we can just hash asBits.
uint64_t u = value.asRawBits();
return HashNumber((u >> 3) ^ (u >> (32 + 3)) ^ (u << (32 - 3)));
// value.data.asBits.
return value.asRawBits();
}
bool
HashableValue::equals(const HashableValue &other) const
{
// Two HashableValues are equal if they have equal bits or they're equal strings.
bool b = (value.asRawBits() == other.value.asRawBits()) ||
(value.isString() &&
other.value.isString() &&
EqualStrings(&value.toString()->asLinear(),
&other.value.toString()->asLinear()));
// Two HashableValues are equal if they have equal bits.
bool b = (value.asRawBits() == other.value.asRawBits());
#ifdef DEBUG
bool same;