Bug 1258619 - Properly sandbox functions inside a template. r=chmanchester

The way functions are being sandboxed in moz.configure land is that
their global namespace is being replaced with a limited and identifiable
dict. And we avoid re-wrapping a function that already received this
treatment.

The problem is that template functions have their global namespace
replaced, and any function that is defined within the template inherits
that global namespace. So when it comes time to wrap those functions
defined in templates with e.g. depends, we detect that they're already
wrapped although they are not, because we look if their global namespace
is of the recognizable type we use when replacing it.

So instead of looking at the global namespace type, keep track of all
functions that are wrapped.
This commit is contained in:
Mike Hommey 2016-03-22 15:31:37 +09:00
Родитель 2ee885572e
Коммит a8db2a2c62
2 изменённых файлов: 6 добавлений и 2 удалений

Просмотреть файл

@ -239,9 +239,9 @@ def command_line_helper():
# All options defined above this point can't be injected in mozconfig_options
# below, so collect them.
@template
@advanced
def early_options():
@depends('--help')
@advanced
def early_options(help):
return set(
option.env

Просмотреть файл

@ -133,6 +133,9 @@ class ConfigureSandbox(dict):
# infered.
self._implied_options = {}
# Store all results from _prepare_function
self._prepared_functions = set()
self._helper = CommandLineHelper(environ, argv)
self._config, self._stdout, self._stderr = config, stdout, stderr
@ -425,7 +428,7 @@ class ConfigureSandbox(dict):
'''
if not inspect.isfunction(func):
raise TypeError("Unexpected type: '%s'" % type(func))
if isinstance(func.func_globals, SandboxedGlobal):
if func in self._prepared_functions:
return func, func.func_globals
glob = SandboxedGlobal(func.func_globals)
@ -441,4 +444,5 @@ class ConfigureSandbox(dict):
func.func_defaults,
func.func_closure
))
self._prepared_functions.add(func)
return func, glob