Bug 1216842 - Part 12: Extrapolate bezier function outside [0,1]. r=birtles

We use the tangent at the each boundary points as same as Chrome does.
This commit is contained in:
Hiroyuki Ikezoe 2016-02-18 14:22:00 +01:00
Родитель 10fdacf755
Коммит c5b7bd9a33
1 изменённых файлов: 34 добавлений и 0 удалений

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@ -35,6 +35,40 @@ double
ComputedTimingFunction::GetValue(double aPortion) const ComputedTimingFunction::GetValue(double aPortion) const
{ {
if (HasSpline()) { if (HasSpline()) {
// Check for a linear curve.
// (GetSplineValue(), below, also checks this but doesn't work when
// aPortion is outside the range [0.0, 1.0]).
if (mTimingFunction.X1() == mTimingFunction.Y1() &&
mTimingFunction.X2() == mTimingFunction.Y2()) {
return aPortion;
}
// For negative values, try to extrapolate with tangent (p1 - p0) or,
// if p1 is coincident with p0, with (p2 - p0).
if (aPortion < 0.0) {
if (mTimingFunction.X1() > 0.0) {
return aPortion * mTimingFunction.Y1() / mTimingFunction.X1();
} else if (mTimingFunction.Y1() == 0 && mTimingFunction.X2() > 0.0) {
return aPortion * mTimingFunction.Y2() / mTimingFunction.X2();
}
// If we can't calculate a sensible tangent, don't extrapolate at all.
return 0.0;
}
// For values greater than 1, try to extrapolate with tangent (p2 - p3) or,
// if p2 is coincident with p3, with (p1 - p3).
if (aPortion > 1.0) {
if (mTimingFunction.X2() < 1.0) {
return 1.0 + (aPortion - 1.0) *
(mTimingFunction.Y2() - 1) / (mTimingFunction.X2() - 1);
} else if (mTimingFunction.Y2() == 1 && mTimingFunction.X1() < 1.0) {
return 1.0 + (aPortion - 1.0) *
(mTimingFunction.Y1() - 1) / (mTimingFunction.X1() - 1);
}
// If we can't calculate a sensible tangent, don't extrapolate at all.
return 1.0;
}
return mTimingFunction.GetSplineValue(aPortion); return mTimingFunction.GetSplineValue(aPortion);
} }