Testing stretchy symbols -- view the source...
A
=
[
x
y
z
w
]
;
x
+
(
a
b
)
;
in binomial formulas
(
n
p
)
=
(
n-1
p
)
+
(
n-1
p-1
)
;
(
a
+
b
)
n
=
a
n
+
(
n
1
)
a
n-1
b
+
...
+
(
n
p
)
a
n-p
b
p
+
...
+
b
n
and elsewhere,
{
a
0
+
1
a
1
+
1
a
2
+
1
a
3
;
a + b
←
;
b + c + d
→
;
a + b +
c + d
→
←
;
(
1
+
5
2
)
;
x
=
-
b
±
b
2
-
4
⁢
a
⁢
c
2
⁢
a
(
{
↑
∫
n
{
n
+
1
)
2
y
↓
}
)
x
→
maps to
y