зеркало из https://github.com/mozilla/gecko-dev.git
71 строка
2.1 KiB
C++
71 строка
2.1 KiB
C++
/* -*- Mode: C++; tab-width: 2; indent-tabs-mode: nil; c-basic-offset: 2 -*-*/
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/* vim: set ts=2 sw=2 et tw=79: */
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/* This Source Code Form is subject to the terms of the Mozilla Public
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* License, v. 2.0. If a copy of the MPL was not distributed with this file,
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* You can obtain one at http://mozilla.org/MPL/2.0/. */
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#include "ipc/IPCMessageUtils.h"
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#include "mozilla/ErrorResult.h"
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#include "mozilla/Assertions.h"
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#include "mozilla/Move.h"
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#ifndef IPC_ErrorIPCUtils_h
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#define IPC_ErrorIPCUtils_h
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namespace IPC {
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template<>
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struct ParamTraits<mozilla::dom::ErrNum> :
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public ContiguousEnumSerializer<mozilla::dom::ErrNum,
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mozilla::dom::ErrNum(0),
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mozilla::dom::ErrNum(mozilla::dom::Err_Limit)> {};
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template<>
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struct ParamTraits<mozilla::ErrorResult>
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{
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typedef mozilla::ErrorResult paramType;
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static void Write(Message* aMsg, const paramType& aParam)
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{
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// It should be the case that mMightHaveUnreportedJSException can only be
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// true when we're expecting a JS exception. We cannot send such messages
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// over the IPC channel since there is no sane way of transferring the JS
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// value over to the other side. Callers should never do that.
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MOZ_ASSERT_IF(aParam.IsJSException(), aParam.mMightHaveUnreportedJSException);
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if (aParam.IsJSException()
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#ifdef DEBUG
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|| aParam.mMightHaveUnreportedJSException
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#endif
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) {
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MOZ_CRASH("Cannot encode an ErrorResult representing a Javascript exception");
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}
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WriteParam(aMsg, aParam.mResult);
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WriteParam(aMsg, aParam.IsErrorWithMessage());
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if (aParam.IsErrorWithMessage()) {
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aParam.SerializeMessage(aMsg);
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}
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}
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static bool Read(const Message* aMsg, void** aIter, paramType* aResult)
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{
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paramType readValue;
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if (!ReadParam(aMsg, aIter, &readValue.mResult)) {
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return false;
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}
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bool hasMessage = false;
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if (!ReadParam(aMsg, aIter, &hasMessage)) {
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return false;
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}
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if (hasMessage && !readValue.DeserializeMessage(aMsg, aIter)) {
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return false;
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}
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*aResult = Move(readValue);
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return true;
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}
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};
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}
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#endif
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