Testing stretchy symbols -- view the source...
(
...
(
(
a
0
+
a
1
)
n
1
+
a
2
)
n
2
+
...
+
a
p
)
n
p
A
=
x
y
z
w
;
x
+
(
a
b
)
;
in binomial formulas
(
n
p
)
=
(
n
-
1
p
)
+
(
n
-
1
p
-
1
)
;
(
a
+
b
)
n
=
a
n
+
(
n
1
)
a
n
-
1
b
+
...
+
(
n
p
)
a
n
-
p
b
p
+
...
+
b
n
and elsewhere,
{
a
0
+
1
a
1
+
1
a
2
+
1
a
3
;
aa
+
bb
⏞
;
b
+
c
+
d
→
;
a
+
b
+
c
+
d
→
←
;
(
1
+
5
2
)
;
x
=
-
b
±
b
2
-
4
⁢
a
⁢
c
2
⁢
a
(
{
↑
∫
n
{
n
+
1
)
2
y
↓
}
)
x
→
maps to
y