зеркало из https://github.com/mozilla/pjs.git
111 строки
3.6 KiB
Bash
Executable File
111 строки
3.6 KiB
Bash
Executable File
#!/bin/sh
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#
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# ***** BEGIN LICENSE BLOCK *****
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# Version: MPL 1.1/GPL 2.0/LGPL 2.1
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#
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# The contents of this file are subject to the Mozilla Public License Version
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# 1.1 (the "License"); you may not use this file except in compliance with
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# the License. You may obtain a copy of the License at
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# http://www.mozilla.org/MPL/
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#
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# Software distributed under the License is distributed on an "AS IS" basis,
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# WITHOUT WARRANTY OF ANY KIND, either express or implied. See the License
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# for the specific language governing rights and limitations under the
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# License.
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#
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# The Original Code is historgram-diff.sh, released
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# Dec 8, 2000.
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#
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# The Initial Developer of the Original Code is
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# Netscape Communications Corporation.
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# Portions created by the Initial Developer are Copyright (C) 2000
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# the Initial Developer. All Rights Reserved.
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#
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# Contributor(s):
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# Chris Waterson <waterson@netscape.com>
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#
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# Alternatively, the contents of this file may be used under the terms of
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# either the GNU General Public License Version 2 or later (the "GPL"), or
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# the GNU Lesser General Public License Version 2.1 or later (the "LGPL"),
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# in which case the provisions of the GPL or the LGPL are applicable instead
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# of those above. If you wish to allow use of your version of this file only
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# under the terms of either the GPL or the LGPL, and not to allow others to
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# use your version of this file under the terms of the MPL, indicate your
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# decision by deleting the provisions above and replace them with the notice
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# and other provisions required by the GPL or the LGPL. If you do not delete
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# the provisions above, a recipient may use your version of this file under
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# the terms of any one of the MPL, the GPL or the LGPL.
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#
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# ***** END LICENSE BLOCK *****
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# histogram-diff.sh [-c <count>] <base> <incr>
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#
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# Compute incremental memory growth from histogram in file <base> to
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# histogram in file <incr>, displaying at most <count> rows.
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# How many rows are we gonna show?
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COUNT=20
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# Read arguments
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while [ $# -gt 0 ]; do
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case "$1" in
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-c) COUNT=$2
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shift 2
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;;
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*) break
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;;
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esac
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done
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BASE=$1
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INCR=$2
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# Sort the base and incremental files so that we can `join' them on
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# the type name
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sort $BASE > /tmp/$$.left
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sort $INCR > /tmp/$$.right
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# Do the join. The `awk' script computes the difference between
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# the base and the incremental files.
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join /tmp/$$.left /tmp/$$.right \
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| awk '{ print $1, $2, $3, $4, $5, $4 - $2, $5 - $3; }' \
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> /tmp/$$.joined
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rm -f /tmp/$$.left /tmp/$$.right
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# Now compute a `TOTAL' row.
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awk '{ tobj1 += $2; tbytes1 += $3; tobj2 += $4; tbytes2 += $5; tdobj += $6; tdbytes += $7; } END { print "TOTAL", tobj1, tbytes1, tobj2, tbytes2, tdobj, tdbytes; }' /tmp/$$.joined \
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> /tmp/$$.sorted
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# Then, we sort by the largest delta in bytes.
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sort -nr +6 /tmp/$$.joined >> /tmp/$$.sorted
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rm -f /tmp/$$.joined
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# Pretty-print, including percentages
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cat <<EOF > /tmp/$$.awk
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BEGIN {
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print " ---- Base ---- ---- Incr ---- ----- Difference ----";
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print "Type Count Bytes Count Bytes Count Bytes %Total";
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}
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\$1 == "TOTAL" {
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tbytes = \$7;
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}
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NR <= $COUNT {
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printf "%-22s %6d %8d %6d %8d %6d %8d %6.2lf\n", \$1, \$2, \$3, \$4, \$5, \$6, \$7, 100.0 * \$7 / tbytes;
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}
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NR > $COUNT {
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oobjs1 += \$2; obytes1 += \$3;
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oobjs2 += \$4; obytes2 += \$5;
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odobjs += \$6; odbytes += \$7;
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}
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END {
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printf "%-22s %6d %8d %6d %8d %6d %8d %6.2lf\n", "OTHER", oobjs1, obytes1, oobjs2, obytes2, odobjs, odbytes, odbytes * 100.0 / tbytes;
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}
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EOF
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# Now pretty print the file, and spit it out on stdout.
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awk -f /tmp/$$.awk /tmp/$$.sorted
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rm -f /tmp/$$.awk /tmp/$$.sorted
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